A) 510 nm
B) 650 nm
C) 400 nm
D) 570 nm
Correct Answer: B
Solution :
Given that, \[2eV\le \text{o }\!\!|\!\!\text{ }\le \text{5}\,\text{eV}\] Wavelength corresponding to minimum and maximum values of work function are \[{{\lambda }_{\max }}=\frac{hc}{E}=\frac{4\times {{10}^{-15}}\times 3\times {{10}^{8}}}{2}\] \[=6\times {{10}^{-7}}m=600\,nm\] and \[{{\lambda }_{\min }}=\frac{hc}{E}=\frac{4\times {{10}^{-15}}\times 3\times {{10}^{8}}}{5}\] \[=2.4\times {{10}^{-7}}m=240\,nm\] Clearly, wavelength range would be \[240\le \lambda \le 600\] Thus, wavelength 650 nm is not suitable for photoelectric effect.
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