A) \[K=-V/2\]
B) \[K=V/2\]
C) \[E=K/2\]
D) \[E=-K/2\]
Correct Answer: A
Solution :
As we know that for the earth and satellite system, Kinetic energy, \[K=\frac{GMm}{2a}\] Potential energy, \[V=-\frac{GMm}{a}\] and total energy, \[E=-\frac{GMm}{2a}\] where, a = radius of the orbit of the satellite and m = mass of the satellite On the basis of above three expressions for the energies, we have \[K=\frac{GMm}{2a}=-\left( -\frac{\frac{GMm}{a}}{2} \right)=-\frac{V}{2}\]
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