A) \[E\sqrt{L/C}\]
B) \[E/R\]
C) infinity
D) \[E\sqrt{C/L}\]
Correct Answer: D
Solution :
When switch is in position a, then capacitor will be charged, such that Charge on capacitor, \[q=CE\] Energy stored in capacitor, \[U={{q}^{2}}/2C\]When switch is in position b, then circuit becomes an LC oscillator. Let amplitude of current in LC circuit be \[{{I}_{o}}.\]From conservation of energy, maximum electrical energy = maximum magnetic energy \[\frac{{{q}^{2}}}{2C}=\frac{1}{2}LI_{0}^{2}\] \[[\because \,q=CE]\] \[\Rightarrow \]\[\frac{{{C}^{2}}{{E}^{2}}}{C}=LI_{0}^{2}\] \[\therefore \]\[{{I}_{0}}=E\sqrt{\frac{C}{L}}\]
You need to login to perform this action.
You will be redirected in
3 sec
