A) 2000 m/s
B) 1414 m/s
C) 1000 m/s
D) 1500 m/s
Correct Answer: B
Solution :
As from the formula, \[{{v}_{rms}}=\sqrt{\frac{3RT}{M}}\] Given that \[{{({{v}_{rms}})}_{CO}}=1000\,m/s\] \[{{(Temp.)}_{{{N}_{2}}}}=600\,K\] Now putting the values, we get \[\frac{{{({{v}_{rms}})}_{CO}}}{{{({{v}_{rms}})}_{{{N}_{2}}}}}=\sqrt{\frac{3R}{3R}\times \frac{{{T}_{CO}}}{{{M}_{CO}}}\times \frac{{{M}_{{{N}_{2}}}}}{{{T}_{{{N}_{2}}}}}}\] \[\frac{1000}{({{v}_{rms}}){{N}_{2}}}=\sqrt{\frac{300}{28}\times \frac{28}{600}}=\frac{1}{\sqrt{2}}\] or,\[{{({{v}_{rms}})}_{{{N}_{2}}}}=1000\times 1.414\] \[=1414\,m/s\]
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