• question_answer At a particular temperature, the ratio of equivalent   conductance   to   specific conductance of a 0.01 N NaCl solution is A)  $10{{\,}^{5}}c{{m}^{3}}$ B)   $10{{\,}^{3}}c{{m}^{3}}$ C)  $10\,c{{m}^{3}}$ D)  $10{{\,}^{5}}c{{m}^{2}}$

As we know that, Equivalent conductance, $(\lambda )$ $\text{=}\,\,\frac{\text{Specific}\,\text{consuctane}\,\text{(K) }\!\!\times\!\!\text{ 1000}}{\text{Concentration}}$ Or, $\frac{\lambda }{K}=\frac{1000}{conc.}$ or, $\frac{\lambda }{K}=\frac{1000\,{{\Omega }^{-1}}c{{m}^{2}}e{{q}^{-1}}}{0.01\,{{\Omega }^{-1}}\,c{{m}^{-1}}}$ (Given, conc. = 0.01 N) or, $\frac{\lambda }{K}={{10}^{5}}\,c{{m}^{3}}\,e{{q}^{-1}}$