A) B
B) Be
C) Mg
D) Al
Correct Answer: A
Solution :
Group II A Group III A Be B Mg Al The electronic configuration of boron is \[2{{s}^{2}}2{{p}^{1}}.\]And electronic configuration of \[{{B}^{+}}\]is \[2{{s}^{2}}.\]Hence, it is difficult to1 remove second electron from \[2{{s}^{2}}\] shell because half-filled and fully filled orbitals are more stable than others.You need to login to perform this action.
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