A) \[i={{\tan }^{-1}}\left( \frac{1}{\mu } \right)\]
B) \[\tan \,i=\mu \]
C) \[\sin \,i=\mu \]
D) \[\cos \,i=\mu \]
Correct Answer: B
Solution :
As situation can be diagrammatically as below From law of reflection \[i=\theta \] Now, \[\theta +r+{{90}^{o}}={{180}^{o}}\] \[\Rightarrow \] \[i+r+{{90}^{o}}={{180}^{o}}\] \[r={{90}^{o}}-i\] Also, from Snells law \[\frac{\sin i}{\sin r}=\mu \Rightarrow \frac{\sin i}{\sin ({{90}^{o}}-i)}=\frac{\sin i}{\cos i}=\mu \] \[\Rightarrow \] \[\tan \,i=\mu \]You need to login to perform this action.
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