A) \[v\]
B) \[-\text{ }v\]
C) \[2v\]
D) Zero
Correct Answer: A
Solution :
Consider the rolling motion of a circular disc as shown in the adjacent diagram. Velocity of point of contact (P) is velocity of point S, \[{{v}_{S}}=v+\omega R=2v\] velocity of centre\[O,{{v}_{o}}=v-\omega (0)=v\] Velocity of a point T at distance R from P is \[{{V}_{T}}=\omega R=Qv.\] Thus possible velocities are \[v,2v\]and 0.You need to login to perform this action.
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