A) 2
B) 3
C) 4
D) 5
Correct Answer: C
Solution :
\[\overset{s{{p}^{2}}}{\mathop{C{{H}_{2}}}}\,=\overset{sp}{\mathop{C}}\,=\overset{s{{p}^{2}}}{\mathop{CH}}\,-\underset{sp}{\mathop{\underset{C\equiv N}{\mathop{\underset{|}{\mathop{\overset{s{{p}^{3}}}{\mathop{CH}}\,}}\,}}\,}}\,-\overset{sp}{\mathop{C}}\,\equiv \overset{sp}{\mathop{CH}}\,\] Thus, number of sp-hybridised \[C=4\]You need to login to perform this action.
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