A) \[m{{v}^{2}}/L\]
B) \[mg\,\cos \theta +m{{v}^{2}}/L\]
C) \[mg\,\cos \theta \,-m{{v}^{2}}/L\]
D) \[mg\,\cos \theta \]
Correct Answer: B
Solution :
The situation is given below . For motion along a vertical circular track, the required centripetal force is along the radius and towards the centre of the circle is given by \[T-mg\,\cos \theta =\frac{m{{v}^{2}}}{L}\] \[\Rightarrow \] \[T=\frac{m{{v}^{2}}}{L}+mg\cos \theta \]You need to login to perform this action.
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