Answer:
Percentage of carbon = \[\frac{12}{44}\times
\frac{mass\,of\,C{{O}_{2}}}{mass\,of\,compound}\times 100\]
\[=\frac{12\times
0.918\times 100}{44\times 0.246}=21.95%\]
Percentage
of hydrogen =
\[\frac{2}{18}\times
\frac{mass\,of\,{{H}_{2}}O}{mass\,of\,compound}\times 100\]
\[=\frac{2\times
0.1014\times 100}{18\times 0.246}=4.58%\]
Composition
of the compound:
C = 21.95%; H =
4.58%; O = 73.47%
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