Answer:
Actual pressure of the gas =715 15=
700 mm
To convert the volume at experimental conditions to volume
at STP
AT STP
\[~{{P}_{1}}=700\text{
}mm;\] \[~{{P}_{2}}=760\text{ }mm\]
\[{{V}_{1}}=50mL;\] \[{{V}_{2}}=?\]
\[{{T}_{1}}=300K;\] \[{{T}_{2}}=273K\]
Applying
general gas equation, \[\frac{{{P}_{1}}{{V}_{1}}}{{{T}_{1}}}=\frac{{{P}_{2}}{{V}_{2}}}{{{T}_{2}}}\]
Volume of
nitrogen at STP, \[{{V}_{2}}=\frac{{{P}_{1}}{{V}_{1}}}{{{T}_{1}}}\times
\frac{{{T}_{2}}}{{{P}_{2}}}\]
\[=\frac{700\times 50\times 273}{300\times 760}=41.9mL.\]
Weight of
organic compound = 0.30 g
Percentage
of nitrogen in the compound
\[=\frac{28}{22400}\times
\frac{{{V}_{2}}}{W}\times 100\]
\[=\frac{28\times
41.9\times 100}{22400\times 0.30}=\mathbf{17}\mathbf{.46%}\]
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