Answer:
% of chlorine
\[=\frac{35.5}{143.5}\times \frac{Mass\,of\,AgCl\,formed}{Mass\,of\,the\,substance}\times
100\]
\[=\frac{35.5}{143.5}\times
\frac{0.5740}{0.3780}\times 100=37.57%\]
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