Answer:
% of sulphur =
\[\frac{32}{233}\times
\frac{Mass\,of\,BaS{{O}_{4}}\,formed}{Mass\,of\,the\,\text{substance}}\times
100\]
\[=\frac{32}{233}\times \frac{0.668}{0.468}\times
100=\mathbf{19}\mathbf{.60%}\]
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