Answer:
(c) is the correct answer, i.e., \[s{{p}^{2}}-s{{p}^{3}}\]orbital
because the name of the organic compound is :
\[{{H}_{2}}\underset{s{{p}^{2}}}{\overset{1}{\mathop{C}}}\,=\underset{s{{p}^{2}}}{\overset{2}{\mathop{C}}}\,H-\underset{s{{p}^{3}}}{\overset{3}{\mathop{C}}}\,{{H}_{2}}-\underset{s{{p}^{3}}}{\overset{4}{\mathop{C}}}\,{{H}_{2}}-\underset{sp}{\overset{5}{\mathop{C}}}\,\equiv
\underset{sp}{\overset{6}{\mathop{C}}}\,H(Hex-1-en-5-yr)\]
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