Answer:
Element
%
Atomic mass
Relative no. of atoms
Simplest ratio
Whole no. ratio
Carbon
24.27
12
\[\frac{24.27}{12}=2.022\]
\[\frac{2.022}{2.018}\approx 1\]
1
Hydrogen
4.07
1
\[\frac{4.07}{1}=4.07\]
\[\frac{4.07}{2.018}\approx 2\]
2
Chlorine
71.65
35.5
\[\frac{71.65}{355}=2018\]
\[\frac{2.018}{2.018}=1\]
1
Empirical formula = \[C{{H}_{2}}Cl\]
Molecular
formula = \[{{\left( C{{H}_{2}}Cl \right)}_{n}}\]
\[n=\frac{Molecular\text{
}mass}{Empirical\text{ }formula\text{ }mass~}=\frac{98.96}{49.5}\approx 2\]
\[\therefore \]Molecular
formula = \[{{(C{{H}_{2}}Cl)}_{2}}={{C}_{2}}{{H}_{4}}C{{l}_{2}}\]
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