Answer:
\[\underset{\underset{{}}{\mathop{1mol}}\,}{\mathop{C{{H}_{4}}+2{{O}_{2}}(g)}}\,\to
C{{O}_{2}}(g)+\underset{\underset{{}}{\mathop{1mol}}\,}{\mathop{2{{H}_{2}}O(g)}}\,\]
Number of moles of
\[C{{O}_{2}}=\frac{\text{mass}\,\text{in}\,\text{garm}}{\text{Gram}\,\text{molecular}\,\text{mass}}\]
\[=\frac{22}{44}=0.5\]
Gram
molecular mass
Number of moles of
methane = Number of moles of \[C{{O}_{2}}\] formed
\[=\text{ }0.5\text{ }mol\]
You need to login to perform this action.
You will be redirected in
3 sec