Answer:
(d) (a) Number of atoms
of
\[He=\frac{Mass}{Molar\,mass}\times
6.023\times {{10}^{23}}\]
\[=\frac{4}{4}\times
6.023\times {{10}^{23}}\]
\[=6.023\times
{{10}^{23}}\]
(b) Number of atoms of \[Na=\frac{46}{23}\times
6.023\times {{10}^{23}}\]
\[=2\times
6.023\times {{10}^{23}}\]
(c) Number of atoms of \[Ca=\frac{0.4}{40}\times
6.023\times {{10}^{23}}\]
(d) Number of atoms of \[He=\frac{12}{4}\times
6.023\times {{10}^{23}}\]
\[=3\times 6.023\times {{10}^{23}}\]
(Greatest)
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