Answer:
(c) Molarity, \[M=\frac{{{w}_{B}}\times
1000}{{{m}_{B}}\times V}\]
\[{{w}_{B}}=0.9g,\,\,\,\,{{m}_{B}}=180,\,\,\,V=1000mL\]
\[\therefore \] \[M=\frac{0.9\times
1000}{180\times 1000}=0.005M\]
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