Answer:
(d) Molality, \[m=\frac{{{w}_{B}}\times
1000}{{{m}_{B}}\times {{w}_{A}}}\]
\[{{w}_{B}}=18.25g,\,\,\,\,{{m}_{B}}=36.5g\,mo{{l}^{-1}}\,,\,\,\,\,\,\,{{w}_{A}}=500g\]
\[\therefore \] \[m=\frac{18.25\times
1000}{36.5\times 500}=1\]
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