Answer:
(b) \[\text{
}\!\!%\!\!\text{
}\,\text{Carbon=}\frac{\text{Mass}\,\text{of}\,\text{Carbon}}{\text{Molar}\,\text{mass}\,\text{of}\,\text{C}{{\text{O}}_{\text{2}}}}\text{
}\!\!\times\!\!\text{ 100}\]
\[=\frac{12}{44}\times
100=27.27\]
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