Answer:
(c) Molecular formula = \[{{(C{{H}_{2}}O)}_{n}}\]
\[n=\frac{\text{Molecular
mass}}{\text{Empirical formula mass }\!\!~\!\!\text{ }}=\frac{180}{30}=6\]
\[\therefore \] Molecular
formula = \[{{(C{{H}_{2}}O)}_{6}}={{C}_{6}}{{H}_{12}}{{O}_{6}}\]
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