question_answer 39)

                  Calculate the number of degrees of freedom of molecules of hydrogen in 1 cc of hydrogen E gas at NTP.

Answer:

                  Number of hydrogen moleucles in 1 cc                 \[\frac{\text{Avogadro }\!\!'\!\!\text{ s}\,\,\text{number}}{\text{Volume}\,\,\text{occupied}\,\,\text{by}\,\text{1}\,\text{g}\,\,\text{mole}\,\,\text{of}\,\text{hydrogen}\,}\]                 At NTP.                 \[=\frac{6.023\,\times {{10}^{23}}}{22400}\,=2.7\,\times {{10}^{19}}\]                 \[{{H}_{2}}\] is diatomic gas and each molecules has degrees of freedom.                 Therefore, number of degrees of freedom w molecules of hydrogen in 1cc of hydrogen gas                 \[=5\times 2.7\times {{10}^{19}}\]                 \[=13.5\times {{10}^{19}}\]