Answer:
Mass of gas, \[M=\mu
\,m,\] where \[\mu \] is the number of moles
When
container suddenly stops, loss in K.E.
\[=\frac{1}{2}\,m\upsilon
_{0}^{2}=\,\frac{1}{2}\,(\mu \,m)\upsilon _{0}^{2}\] ?. (i)
This
loss in K.E. appears as heat energy. AT is the change is temperature, then
\[\Delta
\,U=\,\frac{f}{2}\,\mu \,R\,\Delta T\]
Since
gas is monoatomic, so \[f=3\]
\[\therefore
\] \[U=\frac{3}{2}\,\mu \,R\,\Delta T\] ?. (ii)
From
eqns. (i) and (ii), we get
\[\frac{3}{2}\,\mu
\,R\,\Delta T\,=\frac{1}{2}\,\mu \,m\,\upsilon _{0}^{2}\]
\[\therefore
\] \[\Delta T=\,\frac{m\upsilon _{0}^{2}}{3R}\]
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