Answer:
(c)
\[\frac{x}{a}\,=\,\cos \,\,\omega \,t\] and
\[\frac{y}{a}=\,\sin \,\omega t\]
\[\therefore
\] \[\frac{{{x}^{2}}}{{{a}^{2}}}\,+\frac{{{y}^{2}}}{{{a}^{2}}}\,\,=\,1\]
or \[{{x}^{2}}\,+\,{{y}^{2}}={{a}^{2}}\]
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