Answer:
(d)
\[y=a\sin \omega t+b\cos \omega t\]
This
wage is due to superposition of two waves which are represented by \[{{y}_{1}}=a\,\sin
\,\omega t\] and \[{{y}_{2}}=b\cos
\,\omega t=b\sin \,(\omega t+\frac{\pi }{2})\]
\[\therefore
\] Amplitude of
resultant wave (represented by \[y\])
\[A\,=\sqrt{{{a}^{2}}+\,{{b}^{2}}+\,2ab\,\,\cos
\frac{\pi }{2}}=\,\sqrt{{{a}^{2}}+\,{{b}^{2}}}\]
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