Answer:
Here, \[T=2.06\times
{{10}^{4}}\,N\]
\[\mu
=\] mass/length
\[=\frac{2.10\,kg}{12\,m}=0.175\,kg\,{{m}^{-1}}\]
\[\therefore
\] \[\mu =\,\sqrt{\frac{T}{\mu }}\,=\,\sqrt{\frac{2.06\,\times
\,{{10}^{4}}}{0.175}}\,=\,343\,\,m{{s}^{-1}}\]
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