Answer:
Let nth harmonic be
in resonance with the frequency 1237.5Hz.
In
case of a closed ended pipe.
\[{{v}_{n}}=\,\frac{\upsilon
}{4L}\,=\,\frac{4{{v}_{n}}L}{v}\]
\[=\,\frac{4\times
\,1237.5\,\times \,20\,\times \,{{10}^{-2}}\,}{330}\,=\,3\]
Thus,
third harmonic mode of the pipe will be in resonance with a source of frequency
1237.5 Hz.
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