is treated with excess of 
,
0.2 mol of 
are obtained. The conductivity of solution will correspond
to
(a) 1 : 3 electrolyte (b) 1 : 2 electrolyte
(c) 1 : 1 electrolyte (d) 3 : 1 electrolyte
Answer:
(b)
One mole of 
precipitates one mole of
chloride ion. In the above reaction, when mole 
is
treated with excess of
, 0.2 mole of 
are obtained thus, there must
be two free chloride ions in the solution of electrolyte.
So, molecular formula of complex will be 
and electrolytic solution
must contain 
and two 
as constituent ions. Thus, it
is 1: 2 electrolyte.
Hence, option (b) is the correct.
You need to login to perform this action.
You will be redirected in
3 sec
