Answer:
(i)
Since the rate of reaction of compound 'A' with aq. KOH depends upon the
concentration
of compound 'A' only, therefore, the reaction occurs by mechanism and the compound 'A'
2-bromo-2- methylpropane or tert-butyl bromide.
(ii) Since compound 'B' is optically active and is an isomer of compound
'A' with MF C4HgBr, therefore, compound 'B' must be 2-bromobutane. Further,
since the rate of reaction of compound 'B' with aq. KOH depends both' upon the
concentration of compound 'B' and KOH, therefore, the reaction occurs by mechanism. Since in reactions, nucleophile attacks
from the back side, therefore, the product of hydrolysis
(i.e. 2-butanol) will have inverted configuration w.r.t. to
2-bromobutane.
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