Answer:
10 g of glucose in present in 100 g solution i.e., 10 of glucose has been dissolved in 90 g of water.
Volume of 100 g of solution
= 0.083 L
Number of moles of glucose
Molarity of solution
Mass of water = 90 g = 0.09 kg
Molality of solution
To find mole fraction of each component
Number of moles of glucose
Number of moles of water
Total number of moles = 0.055 + 5 = 5.055.
Mole fraction of glucose
Mole fraction of water
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