Answer:
(b, c)
Cerium (Z = 57) =»
Electronic configuration =
Oxidation
state of Ce = +3, +4
(b) Europium
(Z = 63) Þ Electronic configuration =
Oxidation
state of Eu =+2, +3
(c)
Ytterbium (Z= 70) ^Electronic configuration =
Oxidation
state of Yb = +2, +3
(d) Holmium(
Z=67) Þ Electronic configuration =
Oxidation state of
Ho = +3
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