Answer:
K.E.
of rotation = \[\frac{1}{2}I{{\omega }^{2}}\] \[\therefore
\] \[I=\frac{2\times K.E.\,of\,rotation}{{{\omega }^{2}}}=\frac{\left[
M{{L}^{2}}{{T}^{-2}} \right]}{\left[ {{T}^{-2}} \right]}=\left[
{{M}^{1}}{{L}^{2}}{{T}^{0}} \right]\]
You need to login to perform this action.
You will be redirected in
3 sec