Answer:
\[Y=\frac{{{T}^{x}}.\cos
\theta .\tau }{{{L}^{3}}}\]
\[{{T}^{x}}=\frac{Y{{L}^{3}}}{\cos \theta .\tau }=\frac{\left[ M{{L}^{-1}}{{T}^{-2}}
\right]}{\left[ M{{L}^{2}}{{T}^{-2}} \right]}=1\] \[\therefore \] \[x=0\]
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