Answer:
\[h=\frac{E}{v}=\frac{\left[
ML{{T}^{-2}} \right]L}{\left[ {{T}^{-1}} \right]}=\left[
{{M}^{1}}{{L}^{2}}{{T}^{-1}} \right]\]
\[h=6.62\times
{{10}^{-27}}erg-\sec =6.62\times {{10}^{-27}}\times {{10}^{-7}}joule-\sec
=6.62\times {{10}^{-34}}Js\]
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