Answer:
From
\[F=\frac{G{{m}_{1}}{{m}_{2}}}{{{r}^{2}}}\]
\[G=\frac{F{{r}^{2}}}{{{m}_{1}}{{m}_{2}}}=\frac{\left( ML{{T}^{-2}}
\right)\left( {{L}^{2}} \right)}{{{M}^{2}}}=\left[
{{M}^{-1}}{{L}^{3}}{{T}^{-2}} \right]\]
\[G=6.67\times
{{10}^{11}}k{{g}^{-1}}{{m}^{3}}{{s}^{-2}}=6.67\times {{10}^{-11}}{{\left(
{{10}^{3}}g \right)}^{-1}}{{\left( {{10}^{2}}cm \right)}^{3}}{{s}^{-2}}=6.67\times
{{10}^{-8}}gc{{m}^{3}}{{s}^{-2}}\].
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