Answer:
(a)
If the starting point of fly which is one comer of room is taken as origin of
coordinates, then the coordinates of diametrically opposite comer of room are
(3, 4, 5). So displacement is
\[\overset{\to
}{\mathop{r}}\,=3\hat{i}+4\hat{j}+5\hat{k}\] and \[r=\sqrt{{{3}^{2}}+{{4}^{2}}+{{5}^{2}}}=\sqrt{50}\approx
7m\]
(b)
When the fly walks, then shortest distance travelled is
\[=3+\sqrt{{{4}^{2}}+{{5}^{2}}}=3+\sqrt{41}=9.4m\]
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