Answer:
Draw;
\[(\overset{\to }{\mathop{PQ}}\,)=2\overset{\to }{\mathop{\text{A}}}\,\] .
Where, PQ = 4 cm; and 1 cm represents, magnitude one, of the given vector.
Draw, \[\overset{\to }{\mathop{QS}}\,=\overset{\to }{\mathop{B}}\,\], perpendicular
to \[2\overset{\to }{\mathop{\text{A}}}\,\]. Here, \[QS=3\,cm\].
Now,
\[(2\overset{\to }{\mathop{\text{A}}}\,+\overset{\to }{\mathop{B}}\,)\]will be
represented by \[(\overset{\to }{\mathop{PS}}\,)\]. Here,
\[PS=\sqrt{P{{Q}^{2}}+Q{{S}^{2}}}=\sqrt{{{4}^{2}}+{{3}^{2}}}=5\]
Therefore
magnitude of \[(2\overset{\to }{\mathop{\text{A}}}\,+\overset{\to
}{\mathop{\text{B}}}\,)\]is 5 Fig. 2(c).57.
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