Answer:
Horizontal range = 45 = \[\frac{{{u}^{2}}\sin
2\theta }{g}=\frac{{{30}^{2}}\sin 2\theta }{10}\]
\[\sin 2\theta =\frac{45\times 10}{30\times
30}=\frac{1}{2}=\sin {{30}^{o}}\]or\[\sin {{150}^{o}}\]
\[\text{2}\theta
=\text{3}0{}^\circ \]or\[\text{15}0{}^\circ ~\]or\[\theta =\text{15}{}^\circ
\text{ or 75}{}^\circ \]
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