Answer:
Horizontal range, \[R=\frac{{{u}^{2}}\sin
2\theta }{g}\]
Differentiating it
w.r.t g, we have \[\frac{dR}{dg}=-\frac{{{u}^{2}}}{{{g}^{2}}}\sin
2\theta \][\[\because \,\]u and \[\theta
\] are constant]
or\[dR=-\frac{{{u}^{2}}\sin
2\theta }{g}\frac{dg}{g}=-R\frac{dg}{g}\]or\[\frac{dR}{R}=-\frac{dg}{g}\]
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