Answer:
(a) Refer to page 11/48. The reaction occurs by \[{{S}_{N}}2\] mechanism.
(b) \[{{B}_{2}}{{H}_{6}}\xrightarrow{\,}2\,B{{H}_{3}}\]
\[\underset{\text{Propene}}{\mathop{3\,C{{H}_{3}}CH\,=\,C{{H}_{2}}}}\,+B{{H}_{3}}\xrightarrow{{}}\]\[\underset{\text{Tri-n-propylborane}}{\mathop{{{(C{{H}_{3}}\,C{{H}_{2}}C{{H}_{2}})}_{3}}B}}\,\]
\[\underset{\text{Tri-n-propylborane}}{\mathop{{{(C{{H}_{3}}C{{H}_{2}}C{{H}_{2}})}_{3}}}}\,B+3\,{{H}_{2}}{{O}_{2}}\xrightarrow{O{{H}^{-}},\,{{H}_{2}}O}\]\[\,\underset{\text{Propan-1-ol}}{\mathop{3\,C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH}}\,+\underset{\text{Boric}\,\,\text{acid}}{\mathop{{{H}_{3}}B{{O}_{3}}}}\,\]
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