Answer:
The molecular formula of the
compound and the reaction conditions suggests that the compound is an alcohol
and not an ether. Since it is not resolvable, it is symmetrical and istertiary
butyl alcohol. The corresponding alkane is isobutane. The alcohol has been
formed as follows :
\[C{{H}_{3}}-\underset{\begin{smallmatrix}
| \\
C{{H}_{3}}
\end{smallmatrix}}{\overset{\begin{smallmatrix}
C{{H}_{3}} \\
|
\end{smallmatrix}}{\mathop{C}}}\,-H\xrightarrow{{{H}_{2}}S{{O}_{4}}/heat}\,C{{H}_{3}}-\underset{\begin{smallmatrix}
| \\
C{{H}_{3}}
\end{smallmatrix}}{\overset{\begin{smallmatrix}
C{{H}_{3}} \\
|
\end{smallmatrix}}{\mathop{C}}}\,-S{{O}_{3}}H\]\[\xrightarrow{{{H}_{2}}O}\,C{{H}_{3}}-\underset{\begin{smallmatrix}
| \\
C{{H}_{3}}
\end{smallmatrix}}{\overset{\begin{smallmatrix}
C{{H}_{3}} \\
|
\end{smallmatrix}}{\mathop{C}}}\,-OH\]
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