Answer:
(i) \[\underset{\text{(Primary)}}{\mathop{\overset{5}{\mathop{C}}\,{{H}_{3}}\overset{4}{\mathop{C}}\,{{H}_{2}}\overset{3}{\mathop{C}}\,{{H}_{2}}\overset{2}{\mathop{C}}\,{{H}_{2}}\overset{1}{\mathop{C}}\,{{H}_{2}}Br}}\,\] \[\underset{\text{(Secondary)}}{\mathop{C{{H}_{3}}\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\mathop{C}}\,HC{{H}_{2}}C{{H}_{2}}C{{H}_{3}}}}\,\]
1-Bromopentane would react faster since it is a primary alkyl halide and moreover there is less steric hindrance experienced by the attacking nucleophile.
(ii) \[\underset{\text{(Primary)}}{\mathop{\overset{4}{\mathop{C}}\,{{H}_{3}}\overset{3}{\mathop{C}}\,{{H}_{2}}\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{\overset{2}{\mathop{C}}\,}}\,H\overset{1}{\mathop{C}}\,{{H}_{2}}Br}}\,\] \[\underset{(Tertiary)}{\mathop{C{{H}_{3}}C{{H}_{2}}\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{3}}}}\,\]
1-Bromo-2-methylbutane would react faster since it is a primary alkyl halide while the other is of tertiary nature.
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