Answer:
(i)
(ii) \[\underset{\text{1-Hexanenitrile}}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}C\equiv N}}\,\]\[\xrightarrow[(Hydrolysis)]{{{H}^{+}}/{{H}_{2}}O}\,\underset{\text{Hexanoic}\,\,\text{acid}}{\mathop{C{{H}_{3}}{{(C{{H}_{2}})}_{4}}COOH}}\,\] \[\xrightarrow{N{{H}_{3}}}\,C{{H}_{3}}{{(C{{H}_{2}})}_{4}}COON{{H}_{4}}\]\[\xrightarrow[-{{H}_{2}}O]{\Delta }\,\underset{Hexanamide}{\mathop{C{{H}_{3}}{{(C{{H}_{2}})}_{4}}CON{{H}_{2}}}}\,\,\xrightarrow[(Hofmann-bromamide\,reaction)]{NaOH/B{{r}_{2}}}\,\]\[\underset{\text{1-Aminopentane}}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}N{{H}_{2}}}}\,\]
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