Answer:
We know
that, F = ma
\[10={{m}_{1}}\times
5\]
or \[{{m}_{1}}=\frac{10}{5}=2kg\]
Also, \[{{m}_{2}}=\frac{10}{15}=\frac{2}{3}kg\]
Required acceleration
produced when the masses are tied together
\[a=\frac{F}{m}=\frac{10}{{{m}_{1}}+{{m}_{2}}}=\frac{10}{2+\frac{2}{3}}=\frac{30}{8}=3.75\,\text{m}{{\text{s}}^{-2}}\]
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