Answer:
Here,
initial velocity of sphere, u = 0
Distance travelled, s
= 10 m
Acceleration
of sphere, a = 9.8 \[\text{m}{{\text{s}}^{-2}}\]
Final
velocity of sphere when it just reaches the ground can be calculated using \[{{\upsilon
}^{2}}-{{u}^{2}}=2as\]or\[{{\upsilon }^{2}}-0=2\times 9.8\times
10=196\,\text{m/s}\]
or\[\upsilon
=\sqrt{196}m/s=14m/s\]
Momentum of
the sphere just before it touches the ground = mv
\[=1kg\times
14kg-m{{s}^{-1}}\]
\[=14kg-m{{s}^{-1}}\]
On reaching
the ground, the iron sphere comes to rest, so its final momentum is equal to
zero according to the law of conservation of momentum.
Momentum transferred
to the ground = Momentum of the sphere just before it comes to rest = 14 kg -\[\text{m}{{\text{s}}^{\text{-1}}}\]
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