A) 0
B) \[\text{m}+\text{n}-\text{p}\]
C) \[\text{m}+\text{n}\]
D) \[\frac{mn}{m+n}\]
Correct Answer: A
Solution :
\[\text{1}00\text{1}=\text{91}\times \text{1}0+\text{91}\] ....(1) \[\text{91}0=\text{91}\times \text{1}0+0\] ....(2) Subtracting (2) from (1), we get Solving the two equations, we get \[\therefore \]and \[=\left( \frac{144}{48}+\frac{384}{48}+\frac{240}{48} \right)=3+8+5=16\] \[\frac{a}{b}\] \[\frac{c}{d}=\frac{L.C.M.(a,c)}{H.C.F.(b,d)}\] \[\Rightarrow \]You need to login to perform this action.
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