A) \[(1-8{{S}_{1}}){{S}_{2}}\]
B) \[{{S}_{3}}(1+8{{S}_{1}})\]
C) \[{{S}_{1}}(1+8{{S}_{2}})\]
D) \[{{S}_{1}}(1-8{{S}_{3}})\]
Correct Answer: B
Solution :
\[L.C.M.\] \[\frac{6}{14}and\frac{2}{7}\] \[\Rightarrow \] \[\frac{L.C.M.(6,2)}{H.C.F.(14,7)}=\frac{6}{7}\] \[\text{7}\times \text{13}+\text{13}=\text{1}0\text{4}=\text{23}\times \text{13}\]You need to login to perform this action.
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