A) 10.8
B) 10.2
C) 11.2
D) 10.0
Correct Answer: A
Solution :
Atomic mass \[=\frac{10\times 19+81\times 11}{100}\]\[=\frac{190+891}{100}\] \[=\frac{1081}{100}\] \[=10.81\]You need to login to perform this action.
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