A) 0.1 M
B) 0.2 M
C) 0.05 M
D) 0.25 M
Correct Answer: C
Solution :
0.1M \[AgN{{O}_{3}}\]will react with 0.1M NaCl to form \[0.1M\ NaN{{O}_{3}}\]. But as the volume doubled, conc. of \[NO_{3}^{-}=\frac{0.1}{2}=0.05M\].You need to login to perform this action.
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